Hi, i'm brazilian and i want to say: my english is bad.
I am searching for the packet responsible for the Buum in the source code that have released in the forum, and i found it...Now, i want to share some information about that.
First: The address referenced in the "Server Exploit - Remote Crash" ( 0x00846090 ) is responsible for Disable Login in the server.
Second: If the value of this address is:
- 1 -> The server will block any login.
- 2 -> The server will sleep for 2 minutes every time ( In other words, server will not crash, but it will sleep forever ).
Third: The value of this address will only be changed ( by default ) at server startup from the following ways:
- 1 -> Reading *DISABLE_LOGIN number from Hotuk.ini and writing his value.
- 2 -> If the *DISABLE_LOGIN does not have a number in front of him, the value will be 1.
- 3 -> If the *DISABLE_LOGIN does not exists ( // ), value will be 0.
Fourth: The packet 0x50321010 will only Log the Hack...Now, the simplest solution is to check values in the packets, or use a default log.
Someone more experience can tell me if this is correct? Or correct some mistakes about it.
I am searching for the packet responsible for the Buum in the source code that have released in the forum, and i found it...Now, i want to share some information about that.
First: The address referenced in the "Server Exploit - Remote Crash" ( 0x00846090 ) is responsible for Disable Login in the server.
Second: If the value of this address is:
- 1 -> The server will block any login.
- 2 -> The server will sleep for 2 minutes every time ( In other words, server will not crash, but it will sleep forever ).
Third: The value of this address will only be changed ( by default ) at server startup from the following ways:
- 1 -> Reading *DISABLE_LOGIN number from Hotuk.ini and writing his value.
- 2 -> If the *DISABLE_LOGIN does not have a number in front of him, the value will be 1.
- 3 -> If the *DISABLE_LOGIN does not exists ( // ), value will be 0.
Fourth: The packet 0x50321010 will only Log the Hack...Now, the simplest solution is to check values in the packets, or use a default log.
Someone more experience can tell me if this is correct? Or correct some mistakes about it.