Crack the word and win a subscription!

Quote:

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Originally Posted by -Miyoshi-

4 24 26 6 22 24 16 19 4 25 16 20 17
20 2 20 16 2 8 3 21 9 4 3
18 18 4 14 6 5 18 12 5 1
0 14 10 8 1 13 6 7 4
14 4 2 7 12 7 1 3
10 2 5 5 5 6 2
8 3 0 0 4
5 3 0 4
2 3 4
1 1
1

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dxzfvxpsdyptq
xfxtflgymhg
vvhrjivpie
drnleqjkh
rhfkpkrg
nfiiijf
lgddh
igdh
fgh
ee
e

wtf? o.O

Quote:

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Originally Posted by Jnioms

dxzfvxpsdyptq
xfxtflgymhg
vvhrjivpie
drnleqjkh
rhfkpkrg
nfiiijf
lgddh
igdh
fgh
ee
e

wtf? o.O

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omg.. idk what to do.. I just did something :P XD

Quote:

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Originally Posted by (Original)

Code:

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1 = d = 4
2 = x = 24
3 = z = 26
4 = f = 6
5 = v = 22
6 = x = 24
7 = p = 16
8 = s = 19
9 = d = 4
10 = y = 25
11 = p = 16
12 = t = 20
13 = q = 17

13 = M.

4 4 6 16 16 17 19 20 22 24 24 25 26
D D F P  P  Q  S  T  V  X  X  Y  Z

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If this helps any.

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I thought like dis. :D:

Is the word HI?

Same here.
I'm running out of ideas!
I've already done a lot with numbers.

Its in ascii but i dont know what to do, lol xd

ill give you a little while longer then ill reveal the answer.

How many letters is the word?

13 letters.

I think this is the last shot: 19 11 14 0

eyagwyqtezqur / RBMYCBHLRNHZJ

Plaintext letter A B C D E F G H I J K L M N O P Q R S T U V W X Y Z

Ciphertext letter Q W E R T Y U I O P A S D F G H J K L Z X C V B N M

or 119 111 114 110 if you want it in full ascii

is the word "worn" ? XDD

119 111 114 100 lol

Alright, I give up.
(Not really)

Is the word AGB?
BAG?

Hint: the letter D has a relation to the number 3.

Is the word " I will get mad trying to crack this." ?
However I don't need the sub.. but would be nice if I get it cracked. :ott1:

You only need to use 3 numbers to decode the entire word.

http://www.fohguild.org/forums/attac...read-mhcp7.gif

Does it have anything to do with Pi?
Is it Pi? 3.14?
"Cad"?

223?

/5char

oh its a word not a number?

That's BBC.

word is the same length as the letters.

Dan, why do you insist on making me cry?

chathuringmes

Pie?
3.14?
LOL.

icrackthecode (?) just guessing, lol

right, i'll give away the 3 number sequence to unlock it so from now on whomever cracks it will only get a 3 month sub or an extension to their existing by 3 months.

Numbers required to crack are...

3 , 5 and 7!

well then that basically solves it!

I_love_sheep!

assassin creed!
lol haha

I know!
It's TITS!

ceg?.....

djp.....?

dfhfdfgjdggkh
:D:D

.357 Magnum
Proverbs 3:5-7 NIV - Trust in the LORD with all your heart

Quote:

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Originally Posted by Jnioms

assassin creed!
lol haha

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post the correct word ONLY!

creed


assassin

It's "creed."

Quote:

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Originally Posted by (Original)

Put that sub to good use.

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Who? :?: guessing no1's got it

I figured that one guy was gonna post Creed, and that's it. Isn't it?

Thinking he meant put the word together, like: assassincreed

assassin ?

Ohh shit.
LOL.

nope its not that, i made an error lol. although, it's close :) keep guessing!!!

assassincreed, but sure it's not that. It's one word, not two?

one word.

assassination

Assistance.

yep, bingo. Method was;

Code:

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a s s a s s i n a t i o n
3 5 7 5 3 5 7 5 3 5 7 5 3
d x z f v x p s d y p t q

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muhahha.

upgraded your account to a 3 month azure.

Quote:

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Originally Posted by MentaL

upgraded your account to a 3 month azure.

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Thank-you very much! Without that other guy, I wouldnt of got it.

Oh you bastard. I thought it was 357357357357. Oh well. It almost looked like a word but some things were totally wrong.

loool i started well, i saw ass when start decrypting and i automatically though assasin creed xD
well i will wait for next code ^^

the correct word is: Daniel

Quote:

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Originally Posted by Jnioms

loool i started well, i saw ass when start decrypting and i automatically though assasin creed xD
well i will wait for next code ^^

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Thank's to you I got it!

No problem, hope next time you give me a hand to me :P

What I did:

Code:

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auwcsumpavmqn (original.ROT23)
ysuaqsknytkol (original.ROT21)
wqsyoqilwrimj (original.ROT19)

|
v

a__c__m__v__n
_s__q__n__k__
__s__q__w__m_

---

Actual answer:

Code:

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a___s___a___n
_s_a_s_n_t_o_
__s___i___i__

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So close, yet so far. :zippy:

Quote:

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Originally Posted by jMerliN

What I did:

Code:

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auwcsumpavmqn (original.ROT23)
ysuaqsknytkol (original.ROT21)
wqsyoqilwrimj (original.ROT19)

|
v

a__c__m__v__n
_s__q__n__k__
__s__q__w__m_

---

Actual answer:

Code:

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a___s___a___n
_s_a_s_n_t_o_
__s___i___i__

---

So close, yet so far. :zippy:

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your no match for the mental algorithm.

Interesting how randomness has cracked this so fast.

Edit: nvm didn't read the part where mental helped them. The mystery has disappeared.

Aaawwhh, I was going to let my brother have a look into this -.-
to late.

Quote:

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Originally Posted by Elian.

Aaawwhh, I was going to let my brother have a look into this -.-
to late.

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You've already got a sub. :thumbup1:

Quote:

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Originally Posted by MentaL

yep, bingo. Method was;

Code:

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a s s a s s i n a t i o n
3 5 7 5 3 5 7 5 3 5 7 5 3
d x z f v x p s d y p t q

---

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I don't get it.

Quote:

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Originally Posted by foxx

I don't get it.

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A ROT was done to each character. ROT simply takes a character to the character n characters ahead of it. For instance, a ROT-3 would send a->d, b->e, etc.

That means ROT-26 sends a->a, b->b, c->c, etc, which is the identity map. A simple mathematical fact is that:

ROT-A(ROT-B(x)) = ROT-(A+B)(x)

The numbers he gave was the ROT function used on each character. To undo a ROT-3, you can either do a ROT-(-3) which, mod 26, is the same as ROT-23.

If you undo each ROT that way, you get assassination.

More generally, the set of all ROTs is a set of 26 permutations of the alphabet {a, ..., z}. It is specifically an abelian subgroup of S26.

edited oh lol

Quote:

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Originally Posted by jMerliN

A ROT was done to each character. ROT simply takes a character to the character n characters ahead of it. For instance, a ROT-3 would send a->d, b->e, etc.

That means ROT-26 sends a->a, b->b, c->c, etc, which is the identity map. A simple mathematical fact is that:

ROT-A(ROT-B(x)) = ROT-(A+B)(x)

The numbers he gave was the ROT function used on each character. To undo a ROT-3, you can either do a ROT-(-3) which, mod 26, is the same as ROT-23.

If you undo each ROT that way, you get assassination.

More generally, the set of all ROTs is a set of 26 permutations of the alphabet {a, ..., z}. It is specifically an abelian subgroup of S26.

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or +3 per letter in the sequence listed.

impossible for me to understand...

Quote:

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Originally Posted by Scratch.

impossible for me to understand...

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+3 letters ahead of each one

thats it? o.o

Quote:

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Originally Posted by XcvcX

+3 letters ahead of each one

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well its + the number of the sequence.

Do another one