[PHP]New to SAJAX

**EliteGM** · 15-08-08

Currently i'm abit expirimenting with SAJAX.
I just can get this piece of code to work :P
I'm breaking my head over it for over an hour now :S

PHP Code:


<?

    require("Sajax.php");

    $host = "localhost";

    $user = "floris";

    $pass = "<PASS>";

    $db = "testit";

        

    $sql = mysql_connect($host, $user, $pass);

    $con = mysql_select_db($db, $sql);

    

    if (!$con)

    {

        die("Error[". mysql_errno() ."]: ". mysql_error());

    }

    

    function send($name) {

        $query = mysql_query("INSERT INTO `sajax` VALUES ('$name')"); //I've named my table 'sajax'

        if (!$query)

        {

            die(mysql_error());

        }

    }

    

    sajax_init();

    // $sajax_debug_mode = 1;

    sajax_export("send");

    sajax_handle_client_request();

    

?>

<html>

<head>

    <title>Test</title>

    <script>

    <?

    sajax_show_javascript();

    ?>

        

    function send() {

        var name;

        

        name = document.getElementById("name").value;

        x_send(name);

    }

    </script>

    

</head>

<body>

    <input type="text" name="name" id="name" value="Test" size="10">

    <input type="button" name="check" value="Go"

        onclick="send(); return false;">

</body>

</html>

I have no idea what's wrong..
It should just input the name in the DB, but now it only does a blank input..

**MentaL**

**andrew951** · 15-08-08

PHP Code:


<?php 

    require("Sajax.php"); 

    $host = "localhost"; 

    $user = "floris"; 

    $pass = "<PASS>"; 

    $db = "testit"; 

         

    $sql = mysql_connect($host, $user, $pass); 

    $con = mysql_select_db($db, $sql); 

     

    if (!$con) 

    { 

        die("Error[". mysql_errno() ."]: ". mysql_error()); 

    } 

     

    function send($name) { 

        $query = mysql_query("INSERT INTO `sajax` VALUES ('$name')"); //I've named my table 'sajax' 

        if (!$query) 

        { 

            die(mysql_error()); 

        } 

    } 

     

    sajax_init(); 

    // $sajax_debug_mode = 1; 

    sajax_export("send"); 

    sajax_handle_client_request(); 

     

?> 

<html> 

<head> 

    <title>Test</title> 

    <script> 

    <? 

    sajax_show_javascript(); 

    ?> 

         

    function send() { 

        var name; 

         

        name = document.getElementById("name").value; 

        x_send(name); 

    } 

    </script> 

     

</head> 

<body> 

    <input type="text" name="name" id="name" value="Test" size="10"> 

    <input type="button" name="check" value="Go" 

        onclick="send(); return false;"> 

</body> 

</html>

i had problems yesterday for not putting <?"php" no quote.
try that. im not sure why i had problems. but idk!

**EliteGM** · 16-08-08

Didn't work =x
Thanks for trying though

EDIT:
Found it!
Looked through some sources, and found out I needed a to do in JS e.x: function send_cb { } (add the cb), and do that over with each function i've made.

[PHP]New to SAJAX

Thread Tools

[PHP]New to SAJAX

Re: [PHP]New to SAJAX

Re: [PHP]New to SAJAX

Advertisement