Originally Posted by
chaos123s
maybe...
try that xampp bro ... no need to patch that... just directly go to the php.ini and erase the ";"
Edit line in php.in in:
PHP Code:
C:\xampp\apache\bin\
C:\xampp\php\
Two archives.
Originally Posted by
vjgame123
sir i successfully opened my website. my problem is this
Warning: mssql_query() [function.mssql-query]: message: Invalid object name 'LoginAttempts'. (severity 16) in C:\xampp\htdocs\config\auth.php on line 48
Warning: mssql_query() [function.mssql-query]: Query failed in C:\xampp\htdocs\config\auth.php on line 48
Warning: mssql_fetch_array(): supplied argument is not a valid MS SQL-result resource in C:\xampp\htdocs\config\auth.php on line 49
Warning: mssql_query() [function.mssql-query]: message: Invalid object name 'LoginAttempts'. (severity 16) in C:\xampp\htdocs\config\auth.php on line 52
Warning: mssql_query() [function.mssql-query]: Query failed in C:\xampp\htdocs\config\auth.php on line 52
Warning: mssql_fetch_array(): supplied argument is not a valid MS SQL-result resource in C:\xampp\htdocs\config\auth.php on line 53
----------------------------
$IP = $_SERVER['REMOTE_ADDR'];
$select = mssql_query("SELECT * FROM LoginAttempts WHERE IP = '$IP'");
$selectrow = mssql_fetch_array($select);
$LastLogin = $selectrow["IP"];
$Attempts = $selectrow["Attempts"];
$selectdiff = mssql_query("SELECT DATEDIFF(n,LastLogin,getdate()) FROM LoginAttempts WHERE IP = '$IP'");
$selecteddiff = mssql_fetch_array($selectdiff);
this is my lines.
What website you use?.
