[Release] Pokemon-Area based browser game

[Raftaar]

i know that i have done all that .. the only prob is that the user is not getting any pokemon .. it shows you have got you Charmander or something .. but he never gets it

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and i Will trade the work for work :/

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New funny stuff -> http://prntscr.com/2b428r
http://prntscr.com/2b42g6
http://prntscr.com/2b42lr
http://prntscr.com/2b42rq

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http://prntscr.com/2b42xy

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http://prntscr.com/2b43c5

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http://prntscr.com/2b43sx

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http://prntscr.com/2b441a

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Just working on the mobile version

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If you wanna trade a script for a script or help me out in the development then feel free to pm me

[SimaoMP]

i don't know very much, but i think u have then to refresh the db like write over the db idk the right command for that. That really don't do nothing, have to have another command for update like, charmander have a 0 and then connect to db to put a 1 to that one, i think it's that the way to be done ;)


read the pokemon name
mysql_query("UPDATE ".TB_PREFIX."users SET `pokemon` = `pokemon`+1 WHERE id =".$session->uid."")or die(mysql_error());
/\ /\

[Sphinx]

Need some mysql help!

English:

Spoiler:

I'm making a "Latest captured pokemon" and almost everything works.

I got:

$pokemoninfox = mysql_query("SELECT pokemon_speler.*, pokemon_speler.wild_id, pokemon_speler.user_id, pokemon_speler.gevongenmet
FROM pokemon_speler
ORDER BY pokemon_speler.id DESC LIMIT 1");

while($pokemon = mysql_fetch_array($pokemoninfox)){
$userid = $pokemon['user_id'];
echo $userid;
}

And when i use $wildid = $pokemon['user_id']; i get the user's id but i want to get his name through the id but don't know how.
Help please!

Dutch:

Spoiler:

Ik maak een "Laatst gevangen pokemon" en bijna alles werkt, ik heb:

$pokemoninfox = mysql_query("SELECT pokemon_speler.*, pokemon_speler.wild_id, pokemon_speler.user_id, pokemon_speler.gevongenmet
FROM pokemon_speler
ORDER BY pokemon_speler.id DESC LIMIT 1");

while($pokemon = mysql_fetch_array($pokemoninfox)){
$userid = $pokemon['user_id'];
echo $userid;
}

En wanneer ik $wildid = $pokemon['user_id']; gebruik krijg ik de gebruiker zijn id maar ik wil zijn naam krijgen d.m.v die id maar weet niet hoe.
Help please!

[SimaoMP]

just put $nameuser anything like that and i think it works variable in the mysql for the name of the user like

echo$user
echo$nameuser
echo$username

good luck with that, i will sleep xD

[Raftaar]

User_id = Users's session id

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Make pokemon['user_id'] to gebruiker['user_id'] and it will echo the user's user id

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i don't know very much, but i think u have then to refresh the db like write over the db idk the right command for that. That really don't do nothing, have to have another command for update like, charmander have a 0 and then connect to db to put a 1 to that one, i think it's that the way to be done ;)


read the pokemon name
mysql_query("UPDATE ".TB_PREFIX."users SET `pokemon` = `pokemon`+1 WHERE id =".$session->uid."")or die(mysql_error());
/\ /\

I have done that .. But users are not getting the pkmn .. Pm me and I will show U the script

[KiruHoshino]

<div id="menu">
                    <div class="top"><h2>Esemény</h2><img src="http://forum.ragezone.com/images/icons/ball.gif" alt="<?php echo $txt['title_statistics']; ?>" /></div>
                    <div class="content">
                    	<div class="pokemon_hand_box">
						<ul>
						<?php
						$pokeinfo = mysql_fetch_assoc(mysql_query("SELECT * FROM pokemon_wild AS pw INNER JOIN pokemon_speler AS ps ON ps.wild_id = pw.wild_id WHERE ps.user_id && gehecht = 0 ORDER BY ps.id DESC LIMIT 1"));
						$pokeinfo2 = mysql_fetch_assoc(mysql_query("SELECT gebruikers.username, gebruikers.user_id, ps.user_id FROM pokemon_speler AS ps INNER JOIN gebruikers AS gebruikers ON ps.user_id = gebruikers.user_id WHERE ps.user_id ORDER BY ps.id DESC LIMIT 1"));
						$pokeinfo['user_id'] == $gebruiker['user_id'];
						if($pokeinfo['shiny'] == 1){
						echo '<center><img src="/images/shiny/'.$pokeinfo['wild_id'].'.gif">';
						}else{
						echo '<center><img src="/images/pokemon/'.$pokeinfo['wild_id'].'.gif">';
						}
						echo '<hr>Last catched pokemon: <strong>';
						if($pokeinfo['shiny'] == 1){
						echo 'Shiny '.$pokeinfo['naam'].'</strong></br>';
						}else{
						echo ''.$pokeinfo['naam'].'</strong></br>';
						}
						echo '<strong>Owner:</strong> <a rel="nofollow" href="?page=profile&player='.$pokeinfo2['username'].'">'.$pokeinfo2['username'].'</a></br>
						<strong>Poke ball:</strong> '.$pokeinfo['gevongenmet'].'
						</center>';
						?>
						</ul>
                      </div>
                      </div>
                    <div class="bottom"></div>
                </div>

Copy the code in the index.php file under the team section.

Attachment 131470

Here my work.

[Raftaar]

Here my work.

kiruhoshino .. He means that the last Pokemon caught by the session user ...not the overall

Anyways sphinx can edit yours a bit and make it work

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Sorry guys .. I have emptied my inbox ... Sorry

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WHY DO WE HAVE TO REFRESH EVERYTIME FOR THE BATTLES

[Raftaar]

Can anyone give me a fixed battles for a bug free items page

Note : Items page contains bugs like
Unlimited Items
Any item
Unlimited ICs GOld to all users
and many more bugs

[felixcruzer]

Respect Point System:

Spoiler:

[Raftaar]

Respect point system is easy as shit

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Transferlist for gold -> http://prntscr.com/2bbn40

[felixcruzer]

Respect point system is easy as shit

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Transferlist for gold -> Screenshot by Lightshot

transfer for gold too:-P

[Raftaar]

@felixcruzer check your messages

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@felixcruzer reply

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There is a bug by which we can unban ourselves ..

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@felixcruzer this is your site right ?? Screenshot by Lightshot

[felixcruzer]

@felixcruzer check your messages

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@felixcruzer reply

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There is a bug by which we can unban ourselves ..

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@felixcruzer this is your site right ?? Screenshot by Lightshot

no it's a very old test site where i tried to edit the design i dont touch this site xD

[Raftaar]

LOL okay but message me

[Sphinx]

I actually meant what Kiro posted. Thx.