[SQL]If user is not found?
Hi im using this script :
PHP Code:
<?php
include("includes/connect.php");
if(isset($_GET['user'])){
$rs=mysql_query("SELECT * FROM users WHERE username='".$_GET['user']."'")or die("Blog not found");
while($d=mysql_fetch_assoc($rs)){
echo "Welcome to ".$d['username']."'s Blog!";
}
} ?>
How would you make it so that is the user is not found ex:
user.php?user=LKJELj2l3kj2l3kj
it would echo something?
Thanks
Re: [SQL]If user is not found?
PHP Code:
if(isset($_GET['user']))
{
$query = mysql_query("SELECT * FROM users WHERE username='".$_GET['user']."'")or die("Blog not found");
$res = @mysql_fetch_array($query);
if(count($res) < 1) die('No such user');
echo "Welcome to ".$res['username']."'s Blog!";
}
Re: [SQL]If user is not found?
PHP Code:
<?php
include("includes/connect.php");
if(isset($_GET['user'])){
$rs=mysql_query("SELECT * FROM users WHERE username='".$_GET['user']."'")or die("Blog not found");
while($d=mysql_fetch_assoc($rs)){
echo "Welcome to ".$d['username']."'s Blog!";
}
else{
echo "Username not found.";
}
?>
mines probably wrong but its what i use on my DMS
Re: [SQL]If user is not found?
Quote:
Originally Posted by
Hidden
Hi im using this script :
PHP Code:
<?php
include("includes/connect.php");
if(isset($_GET['user'])){
$rs=mysql_query("SELECT * FROM users WHERE username='".$_GET['user']."'")or die("Blog not found");
while($d=mysql_fetch_assoc($rs)){
echo "Welcome to ".$d['username']."'s Blog!";
}
} ?>
How would you make it so that is the user is not found ex:
user.php?user=LKJELj2l3kj2l3kj
it would echo something?
Thanks
Well for starters, why are you using a while loop if there will only be one row? Also, why are you using the string concatenation operator when you are using double quotes? Plus, indentation couldn't hurt.
PHP Code:
<?php
include("includes/connect.php");
if (isset($_GET['user'])){
$rs = mysql_query("SELECT * FROM users WHERE username='".$_GET['user']."'")or die("Blog not found");
$user = mysql_fetch_assoc($rs);
if ($user !== FALSE) {
echo "Welcome to {$user['username']}'s Blog!";
}
else {
echo 'Whatever';
}
} ?>
Honestly, write better code.
Re: [SQL]If user is not found?
Quote:
Originally Posted by
King Izu
Well for starters, why are you using a while loop if there will only be one row? Also, why are you using the string concatenation operator when you are using double quotes? Plus, indentation couldn't hurt.
PHP Code:
<?php
include("includes/connect.php");
if (isset($_GET['user'])){
$rs = mysql_query("SELECT * FROM users WHERE username='".$_GET['user']."'")or die("Blog not found");
$user = mysql_fetch_assoc($rs);
if ($user !== FALSE) {
echo "Welcome to {$user['username']}'s Blog!";
}
else {
echo 'Whatever';
}
} ?>
Honestly, write better code.
Just starting it off, could of made it post their age or anything
Re: [SQL]If user is not found?
Re: [SQL]If user is not found?
Quote:
Originally Posted by
Hidden
Just starting it off, could of made it post their age or anything
loop would be required if you'd want to print like all users, but for only one, it's senseless.
anyway this is how I'm doing it(bit messy because of redoing few things after applying mod_rewrite..)
PHP Code:
//get id from that user with username from get, because of fucking mod_rewrite
$name = $_GET['u'];
$query = "SELECT * FROM user WHERE username = '$name'";
$result = mysql_query($query);
$array = mysql_fetch_array($result);
//get everything from users where id is $name's id
$id = $array['id'];
$timesviewed = views_user($id);
$query = "
SELECT
user.*,
userdetails.*
FROM
user,userdetails
WHERE
userdetails.userID = '$id'
AND
user.ID = '$id'
";
$result = mysql_query($query);
$array = mysql_fetch_array($result);
//check if id from $_GET contains a profile lol
if( $array['userID'] == NULL )
{
index_redir();
echo "This profile doesn't exist, redirecting to the main page";
}
//if it does exist..
else
{
/*
**********
print all user's details
**********
*/
}