[PHP] rand & eregi

Hello, i'm writing a script with my friend for a sort of chatbot.

now we have this piece of code:

PHP Code:

---

                if(eregi('snap',$msg) && eregi('niet',$msg)) { 
                    $array = array("snap1", "snap2", "snap3", "snap4", "snap5");
                    $msg = array_rand($array, 5);
                } 


---

Now what it needs to do is: If it finds the word "snap" and the word "niet" in the send message, it will pick a randomly message (snap1, snap2, snap3, snap4 or snap5) and give that to variable $msg
(later on in the script it will search for $msg in my database)

But i keep getting my error message (the message when a word isn't in the database), how can i fix this?? =]

Could you please post the error message?

Thats the point, it doesn't have an error message, it just doesn't get to the point where it assigns a random string to $msg

You need to post more of your script then, because I haven't got a clue what you're saying here.

Okay first i got this:

PHP Code:

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 $msg = strip_tags(strtolower(base64_decode($_POST['msg']))); 


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Which will save the message send by the person (this code is okay, i got it from the maker of the program to handle the stuff)

Then

PHP Code:

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$msg = mysql_real_escape_string ($msg); 


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Looks if poeple are not trying to do a mysql injection

After that the random part comes:

PHP Code:

---

                if(eregi('snap',$msg) && eregi('niet',$msg)) { 
                    $array = array("snap1", "snap2", "snap3", "snap4", "snap5");
                    $msg = array_rand($array, 5);
                } 


---

Then it gets $msg out of the database:

PHP Code:

---

$query = "SELECT * FROM `msg` WHERE `bericht` = '" . $msg . "'";
        $res = mysql_query($query);
        $nummers = mysql_num_rows ($res);
            if ($nummers != "0") {
                while($rows = mysql_fetch_row($res)){
                    $antwoord = $rows[1];
                }[ 


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(not sure how this script works, someone else gave it me)

Then we get a default message if it can't find the word in the database:

PHP Code:

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if (empty($antwoord)) {
                      $antwoord = "Ik snap u niet '" . $nick . "'. Mijn database is nog niet goed gevuld :P
Ik zoek namelijk nog scripters die mijn AI kunnen coderen. 
Interesse? Mail Guild-Power@live.nl!";
            } 


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And finaly it will send out a response to the person who talked to me

Code:

---

<Response>
<Message>
<?
echo $antwoord;
?>
</Message>
</Response>

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(this part is also good becuase i got it from the maker of the program)

Quote:

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Originally Posted by G_NETWORK

Hello, i'm writing a script with my friend for a sort of chatbot.

now we have this piece of code:

PHP Code:

---

                if(eregi('snap',$msg) && eregi('niet',$msg)) { 
                    $array = array("snap1", "snap2", "snap3", "snap4", "snap5");
                    $msg = array_rand($array, 5);
                } 


---

Now what it needs to do is: If it finds the word "snap" and the word "niet" in the send message, it will pick a randomly message (snap1, snap2, snap3, snap4 or snap5) and give that to variable $msg
(later on in the script it will search for $msg in my database)

But i keep getting my error message (the message when a word isn't in the database), how can i fix this?? =]

---

PHP Code:

---

$msg=$array[rand(0,(count($array)))] 


---

try this instead

Nonono.... The rand is working, but the other piece (eregi) doesn't work properply.. =[

Try using ereg instead of eregi.

EDIT: Nevermind, there shouldn't be a difference.

Quote:

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Originally Posted by Pieman

Try using ereg instead of eregi.

EDIT: Nevermind, there shouldn't be a difference.

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that's what i wanted to say, it wouldn't make a diffirence, except for the fact that eregi ignores higher case letters =]

does it work when you echo something out of the if() statement?

If it does then that's not your problem

Already fixed.. =]

I needed to store the string in a var =]