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Hi there all! :D
I was just wondering, is there like a function that returns all current sessions?
Maybe something like a session_array() which returns something like
Array
(
guest => Array ( )
admin => Array ( )
)
Or maybe like a session_count($session_name), where if you did $_SESSION['guest'], and you did session_count("guest"), it would return the number of those sessions?
Any help is appreciated.
So basically you want a function that returns all session variable?
Just wanna make sure
Yeah, cuz i'm doing something like
if(!isset($_SESSION['id']))
$_SESSION['memgroupid'] = 1;//Guest MemberGroup ID
function getGuests()
{
//Count memgroupid sessions with a value of 1.
}
OK. You can print all session variable with this:
Maybe this is what you needPHP Code:<?php
session_start();
Print_r ($_SESSION);
?>
hmmm...
Then could I do
count($_SESSION['memgroupid'])?
It's that easy?
:O:
Btw I am still not sure what you are trying to do.
You can try to
Basically, if a guest comes to my site, I set them with the session memgroupid, with the value of 1 (in the mysql db, 1 is the guest group)
Now, in an infobox, I want it to show the amount of guests.
So would I do count($_SESSION['memgroupid'])?
Does that even work? O_O
Yep, because $_session is a variable.Quote:
Originally Posted by SimpleBB
Posted via Mobile Device
Ok, thanks. :D
Butjust to make sure...
http://71.141.99.165/test.php
What number do you see?
I see a 1. You're doing it wrong.
Well, this is my code:
what's wrong?PHP Code:<?php
session_start();
$_SESSION['mem'] = 1;
echo count($_SESSION['mem']);
?>
The function count() counts the number of values stored in an array. You're not using it correctly. Here's a good tutorial: http://www.devarticles.com/c/a/PHP/T...line-With-PHP/
But isn't $_SESSION['memgroupid'] an array?
When I print_r $_SESSION, memgroupid is an array.
---------- Post added at 04:55 PM ---------- Previous post was at 04:48 PM ----------
About http://www.devarticles.com/c/a/PHP/T...line-With-PHP/,
how do i make it read $_SESSIONs with only $_SESSION['memgroupid'], and not every single session file?
yes, follow murawd. in summary - each array must be treated in a variable as a value. for that you will need to loop a sequence to initialise every variable for each array - read the tutorial murawd has directed you.
Posted via Mobile Device
:o :o :oQuote:
Originally Posted by simplebb
Ohh... I got what SimpleBB wants to do.
Basically he wants to show number of guests on web-site.
I have an idea how to make it in head, but can't explain it cause of my english ...
Try.
It'll be good for your english, to try.
Most importantly, it'll help me! >:D
Here is guide that will help. But sucks that it requires mysql.
http://www.newbiesparadise.com/tutor...ts-online.html
If you want you can change that script a little bit and make it write data in txt file
try
$array = $_SESSION['memgroupid'];
$count = count($array);
for($i = 0;$i < $count;$i++)
{ print "$i"; }
as simple as that, i should think. I have not worked on web page coding for a year, and i miss the excitement of solving problems, the harder the better.
Posted via Mobile Device
Doesn't work.Quote:
Originally Posted by IQstim
Anyyways, i now know that counting it won't work, cuz the memgroupid goes into session once, not equal to the amount of sessions.
check the link that i have sent in my previous post.Quote:
Originally Posted by SimpleBB
That should help you
That does seem to work.
Does anyone else have a faster or possibly, a solution that will get guests faster, with less memory usage?
Check this: http://98.246.30.179/test.php
I have setted this up using guide from here: http://www.newbiesparadise.com/tutor...ts-online.html
Everything works perfectly ;)
Lol, who's the other person?
me and you
there were other 2-3 persons