- Joined
- May 30, 2008
- Messages
- 558
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- 64
okay, so im still learning in GD n stuff
I need the image to be a variable so I can change the image in the database like so i can make it set the image from an egg to anything by choosing between 2 image names in the database from using 2 time stamps like one is when it was made and the second when it should be hatched, so yeah i seem to have this working
but when I try a variable as the image name like
it doesnt work
any help ?
I need the image to be a variable so I can change the image in the database like so i can make it set the image from an egg to anything by choosing between 2 image names in the database from using 2 time stamps like one is when it was made and the second when it should be hatched, so yeah i seem to have this working
PHP:
<?php
$imagename = "egg.png";
function LoadPNG($imgname)
{
$im = @imagecreatefrompng($imgname);
return $im;
}
header('Content-Type: image/png');
$img = LoadPNG('egg.png');
$tc = imagecolorallocate($img, 255, 255, 255);
$tc2 = imagecolorallocate($img, 255,0,0);
imagestring($img, 1, 5, 5, "http://Krazey-Gaming.net/". $imgname, $tc);
imagepng($img);
imagedestroy($img);
?>
but when I try a variable as the image name like
PHP:
<?php
$icon = "egg.png";
$imagename = "$icon";
function LoadPNG($imgname)
{
$im = @imagecreatefrompng($imgname);
return $im;
}
header('Content-Type: image/png');
$img = LoadPNG('$icon');
$tc = imagecolorallocate($img, 255, 255, 255);
$tc2 = imagecolorallocate($img, 255,0,0);
imagestring($img, 1, 5, 5, "http://Krazey-Gaming.net/". $imgname, $tc);
imagepng($img);
imagedestroy($img);
?>
it doesnt work
