Help with my statistics its messed up!

[MedinaJoshua]

This is the code:

 <div class="habblet-container ">		
<div class="cbb clearfix red "> 

<h2 class="title">Hotel Statistics</h2>
<div class="box-content"> 
<div style="text-align: left;">
		<Center>
                        There are <strong>
                        <?php
$query = mysql_query("SELECT COUNT(*) AS aantalbadges FROM users") or die(mysql_error());
$data = mysql_fetch_assoc($query);

echo $data['aantalbadges'];
?></strong> Registered Members on Hangout.<br />
                        There are <strong><?php $query = mysql_query("SELECT COUNT(*) AS aantalkamers FROM users WHERE `vip` >= '1'") or die(mysql_error());
$data = mysql_fetch_assoc($query);

echo $data['aantalkamers'];
?></strong> VIP Members on Hangout.<br />
                        There are <strong><?php
$query = mysql_query("SELECT COUNT(*) AS aantalmeubels FROM furniture") or die(mysql_error());
$data = mysql_fetch_assoc($query);

echo $data['aantalmeubels'];
?></strong> Furniture items on Hangout.<br />
                        There are <strong><?php $query = mysql_query("SELECT COUNT(*) AS aantalkamers FROM users WHERE `rank` >= '6'") or die(mysql_error());
$data = mysql_fetch_assoc($query);

echo $data['aantalkamers'];
?></strong> Staff Members on Hangout.<br />
                        There are <strong><?php
$query = mysql_query("SELECT COUNT(*) AS aantalkamers FROM site_news") or die(mysql_error());
$data = mysql_fetch_assoc($query);

echo $data['aantalkamers'];
?></strong> News Articles on Hangout.<br />
                        There are <strong><?php
$query = mysql_query("SELECT COUNT(*) AS aantalkamers FROM bans") or die(mysql_error());
$data = mysql_fetch_assoc($query);

echo $data['aantalkamers'];
?></strong> Banned Users on Hangout.<br />
                        There are <strong><?php
$query = mysql_query("SELECT COUNT(*) AS aantalkamers FROM user_wardrobe") or die(mysql_error());
$data = mysql_fetch_assoc($query);

echo $data['aantalkamers'];
?></strong> saved outfits on Hangout.<br />
                        There are <strong><?php
$query = mysql_query("SELECT COUNT(*) AS aantalkamers FROM rooms") or die(mysql_error());
$data = mysql_fetch_assoc($query);

echo $data['aantalkamers'];
?></strong> Rooms on Hangout.<br />
                        There are <strong>352</strong> Filtered words in rooms on Hangout.<br />
                        There are <strong><?php
$query = mysql_query("SELECT COUNT(*) AS aantalkamers FROM bots_petdata") or die(mysql_error());
$data = mysql_fetch_assoc($query);

echo $data['aantalkamers'];
?></strong> Pets on Hangout.<br />
                        There are <strong><?php
$query = mysql_query("SELECT COUNT(*) AS aantalkamers FROM bots") or die(mysql_error());
$data = mysql_fetch_assoc($query);

echo $data['aantalkamers'];
?></strong> Bots on Hangout.<br />
                        There are <strong><?php
$query = mysql_query("SELECT COUNT(*) AS aantalkamers FROM groups") or die(mysql_error());
$data = mysql_fetch_assoc($query);

echo $data['aantalkamers'];
?></strong> Groups on Hangout.
	</div></center>

</div>
</div>
</div>

Screenshot:

 

[Tafelglotzer]

Any errors in the console?

 

[MedinaJoshua]

L10N or something.

 

[Tafelglotzer]

How about a screenshot lol

 

[MedinaJoshua]

How about a screenshot lol

https://prnt.sc/opsq6y
https://prnt.sc/opsq1n

Sorry here you go haha

 

[KittyChloe]

First off, that code is... horrendously eye tearing.

Secondly...

what is exactly not working? In your first post, you hand us a couple of DOM elements and some... disgusting database queries... then... you hand us a javascript error.


Also please, if you're new to coding... pleaaaase get a proper IDE and don't use notepad.

Proper IDEs to start off with:

Visual Studio Code,
Sublime Text 3,
Brackets

See blog posts:
https://tms-outsource.com/blog/posts/web-development-ide/​

 

[luduz]

This isn't your stats causing the error. Check your header.php and ensure all stylesheets are correctly linked!