Crack the word and win a subscription!

[Livar]

Aaawwhh, I was going to let my brother have a look into this -.-
to late.

You've already got a sub.

 

[foxx]

yep, bingo. Method was;

a s s a s s i n a t i o n
3 5 7 5 3 5 7 5 3 5 7 5 3
d x z f v x p s d y p t q

I don't get it.

 

[jMerliN]

I don't get it.

A ROT was done to each character. ROT simply takes a character to the character n characters ahead of it. For instance, a ROT-3 would send a->d, b->e, etc.

That means ROT-26 sends a->a, b->b, c->c, etc, which is the identity map. A simple mathematical fact is that:

ROT-A(ROT-B(x)) = ROT-(A+B)(x)

The numbers he gave was the ROT function used on each character. To undo a ROT-3, you can either do a ROT-(-3) which, mod 26, is the same as ROT-23.

If you undo each ROT that way, you get assassination.

More generally, the set of all ROTs is a set of 26 permutations of the alphabet {a, ..., z}. It is specifically an abelian subgroup of S26.

 

[ezpzzz]

edited oh lol

 

[MentaL]

A ROT was done to each character. ROT simply takes a character to the character n characters ahead of it. For instance, a ROT-3 would send a->d, b->e, etc.

That means ROT-26 sends a->a, b->b, c->c, etc, which is the identity map. A simple mathematical fact is that:

ROT-A(ROT-B(x)) = ROT-(A+B)(x)

The numbers he gave was the ROT function used on each character. To undo a ROT-3, you can either do a ROT-(-3) which, mod 26, is the same as ROT-23.

If you undo each ROT that way, you get assassination.

More generally, the set of all ROTs is a set of 26 permutations of the alphabet {a, ..., z}. It is specifically an abelian subgroup of S26.

or +3 per letter in the sequence listed.

 

[Scratch]

impossible for me to understand...

 

[XcvcX]

impossible for me to understand...

+3 letters ahead of each one

 

[Scratch]

thats it? o.o

 

[MentaL]

+3 letters ahead of each one

well its + the number of the sequence.

 

[Retro!]

Do another one