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Title says it all.
Dynamic Online users count PHP code?
- Thread starter Cloudflare
- Start date
I think we would need a little more information on what you are looking for. What kind of server are you running? And what CMS are you using?
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It wouldn't matter "Dynamic users online count"
Auto updates without refreshing page.
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PHP alone wouldn't do this. And yes it does matter what kind of server you are running. Are you running an oldskool server, like debbo? or are you running a server that requires an emulator and uses .swfs and MySQL? If you are running a server that uses MySQL, then you can use Javascript to loop through and refresh the online count. But that would be a big load on the webhost.
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?? Not wrong. I develop websites for money. I am pretty advanced with PHP. PHP has never been able to update text on a website without a page reload. I would use jQuery (Javascript Library) to send an AJAX call to a PHP update script, and set the online count to that value via jQuery.
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I coded this just for you 
Like me if it works,
if not, ill re-code it
$onlineurl = file_get_contents('ONLINE LINK HERE'); // T.EX blablabla.com/online.php? lol$result = mysql_query("SELECT * FROM server_status");$online = "Users Online!";$row = mysql_fetch_array( $result ); $image = imagecreatefrompng('images/banner.png'); $font_color = imagecolorallocate($image, 255, 0, 0); imagefttext($image, 20, 0, 417, 30, $font_color, './arial.ttf', $row['users_online']); imagefttext($image, 8, 0, 398, 45, $font_color, './arial.ttf', $online); imagefttext($image, 20, 0, 394, 77, $font_color, './arial.ttf', $num_rows); header('Content-type: image/png'); imagepng($image); imagedestroy($image);
Like me if it works,
if not, ill re-code it
$onlineurl = file_get_contents('ONLINE LINK HERE'); // T.EX blablabla.com/online.php? lol$result = mysql_query("SELECT * FROM server_status");$online = "Users Online!";$row = mysql_fetch_array( $result ); $image = imagecreatefrompng('images/banner.png'); $font_color = imagecolorallocate($image, 255, 0, 0); imagefttext($image, 20, 0, 417, 30, $font_color, './arial.ttf', $row['users_online']); imagefttext($image, 8, 0, 398, 45, $font_color, './arial.ttf', $online); imagefttext($image, 20, 0, 394, 77, $font_color, './arial.ttf', $num_rows); header('Content-type: image/png'); imagepng($image); imagedestroy($image);
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That is all PHP, there is no way that is going to by dynamic and update every time someone logs into the hotel.
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I coded this just for you
Like me if it works,
if not, ill re-code it
$onlineurl = file_get_contents('ONLINE LINK HERE'); // T.EX blablabla.com/online.php? lol$result = mysql_query("SELECT * FROM server_status");$online = "Users Online!";$row = mysql_fetch_array( $result ); $image = imagecreatefrompng('images/banner.png'); $font_color = imagecolorallocate($image, 255, 0, 0); imagefttext($image, 20, 0, 417, 30, $font_color, './arial.ttf', $row['users_online']); imagefttext($image, 8, 0, 398, 45, $font_color, './arial.ttf', $online); imagefttext($image, 20, 0, 394, 77, $font_color, './arial.ttf', $num_rows); header('Content-type: image/png'); imagepng($image); imagedestroy($image);
That is PHP & you didnt code that you took that from a thread on here, that's a dynamic users online banner.
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