[PHP] Simple & Troublesome

[Delici0us]

Hello RaGEZONE

I am stuck on the IF function in PHP. I am trying to write something so simple but failing, so if any of you could help I would be greatfull.

I would like to write something like this... I have writen it in Puseado code.

IF user_id has badge_code in database then give this badge else give the other badge

 

[Bonitão]

Ohh.. now I understand.. Whoops.. Well, you have to tell us more info.. Like is it using a MySQL database, etc.

 

[s-p-n]

$default_badge = 'CRAP_BADGE_CODE';

$query = mysql_query('SELECT `badge_code` FROM `users` WHERE `user_id` = "'.$user_id.'"') or die(mysql_error());

if(mysql_num_rows($query)>0)
{
    $row = mysql_fetch_assoc($query);
    if(strlen($row['badge_code'])>0)
    {
        $users_badge = $row['badge_code'];

    } else $users_badge = $default_badge;

} else $users_badge = $default_badge;